Abox of unknown mass is sliding with an initial speed vi = 5.10 m/s across a horizontal frictionless warehouse floor when it encounters a rough section of flooring d = 3.10 m long. the coefficient of kinetic friction between the rough section of flooring and the box is 0.100. using energy considerations, determine the final speed of the box (in m/s) after sliding across the rough section of flooring.

5.2 m/s.

Explanation:

Let’s determine the initial kinetic energy of the box.

KE = ½ * m * 5.8^2 = m * 16.82

Let’s determine the friction force.

Ff = 0.1 * m * 9.8 = m * 0.98

To determine the work done by the friction force, multiply by 3.4 meters.

Work = m * 3.332

To determine the final kinetic energy of the box, subtract these two numbers.

KE = m * 13.448

½ * m * v^2 = m * 13.448

v = √26.956

Hope this helps :)

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

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