Door 1 had its knob on the opposite side of the door as the hinges and door 2 has its door knob close to the hinge side of the door . suppose both doors require he same amount of torque to open. which door would require you to push for a greater distance to open it?

Explanation:

Torque is defined as the product of force applied and the perpendicular distance.

Torque = force x distance

It is a vector quantity and its SI unit is Nm .

According to the question, the torque is same in both the cases. So, the distance of knob 2 is less than the distance of knob 1, so we have to apply more force on knob 2 to open the door.

the area between the graph and the t axis

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s