Ajet airplane is in level flight. the mass of the airplane is m=8930 kg. the airplane travels at a constant speed around a circular path of radius =8.23 mi and makes one revolution every t=0.109 h. given that the lift force acts perpendicularly upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane?

88.95 kN

Explanation:

Given

mass of Plane =8930 kg

radius of circular path

Time period =0.109 h

Let F be the lift force

If Plane is making an with horizontal then F will make an angle of w.r.t horizontal

Thus

---1

------2

and is given by

Divide 2 & 1

Substitute in 1

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.