Physics, 14.10.2019 18:30 miwptv105own5u8

Aperson standing at the edge of a seaside cliff kicks a stone, horizontally over the edge with a velocity of 18 m/s. the cliff is 52 m above the waters surface
a. how long does it take for the stone to fall to the water
b. what is the vertical velocity component of the stone just before it hits the water
c. what is the horizontal velocity component of the stone just before it hits the water
d. what is the total velocity of the stone just before it hits the water ?

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Answer from: halbrookc7082

A) The time taken by the stone to reach the ground will be 3.257 Seconds

B) The Initial vertical velocity will be zero

C) The horizontal velocity doesn’t change, so it remains the same i.e., 18m/s.

D) The total velocity of the stone just before it hits the water is 36.645 m/s.

A)Explanation :

When the stone is kicked, there are two components act on the stone. One is in the horizontal direction, and the other in downward vertical direction.

Also Initial vertical component of velocity will be zero as the stone is kicked horizontally.

So, the time taken will be given by applying Newton’s Equation of Motion

Or, y= $v_{i} t+\frac{1}{2} g t^{2}$

Where y = vertical downward distance

v_i =initial vertical velocity=0 m/s

t = time taken to reach the ground

Substituting the values in the above equation, we find

-52 = 0 + $\frac{-9.8 \times t^{2}}{2}$

or, t^2 = $\frac{-52 \times 2}{-9.8}$

or, t = $\sqrt{\frac{1040}{98}}$ = 3.257 s

B) Explanation

The Initial vertical velocity will be zero as the stone is kicked horizontally

C)Explanation

The horizontal velocity component is not under the influence of gravity, so it remains the same, and moves constant velocity horizontally.

D) Explanation

We will firstly find the final vertical velocity using one of the equations of motion

v_f = $\mathrm{v}_{\mathrm{i}}+\mathrm{at}^{2}$

Substituting the values in the above equation, we find

v_f = $0-9.8 \times 3.257$ =-31.92 m/s

Now, Total Velocity (v) is given by

v = $\sqrt{v_{x}^{2}+v_{y}^{2}}$

where,

v_x = Horizontal velocity

v_y = Vertical velocity

Substituting the values in the above equation, we find

v = $\sqrt{18^{2}+31.92^{2}}$ = 36.645 m/s

Answer from: Quest

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Answer from: Quest

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

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