Ball a is attached to one end of a rigid massless rod, while an identical ball b is attached to the center of the rod, as shown in the figure. each ball has a mass of m =
0.450 kg, and the length of each half of the rod is l = 0.420 m. this arrangement is held by the empty end and is whirled around in a horizontal circle at a constant rate,
so that each ball is in uniform circular motion, ball a travels at a constant speed of va = 5.10 m/s. find (a) the tension of the part between a and b of the rod and (b)
the tension of the part between b and the empty end.

Explanation:

From the given data angular speed is equal to

                    w=VA/RA

                     w=5.1/2*0.42

                        =6.07 rad/s

      a)               TAB=m*a

                             =m*(RA)*()

                              =0.45*(2*0.42)(

                              =13.92 N

     b)                 TBO=TAB+m*a

                                  =13.92+0.45*0.42*

                                  =20.88 N

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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