A15.0-gram lead ball at 25.0°c was heated with 40.5 joules of heat. given the specific heat of lead is 0.128 j/g∙°c, what is the final temperature of the lead?

Explanation:

The equation that relates heat Q with the temperature change of a substance of mass m and specific heat c is .

We want to calculate the final temperature T, so we have:

Which for our values means (in this case we do not need to convert the mass to Kg since c is given in g also and they cancel out, but we add to our temperature in to have it in as it must be):

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.