Avessel is filled with a liquid of density 1900 kg/m3 . there are two holes (one above the other) in the side of the vessel. liquid streams out of both of these holes in a horizontal direction. the upper hole is a distance 19 m below the surface of the liquid and the lower hole is a distance 117 m below the surface of the liquid. the acceleration of gravity is 9.8 m/s 2 . at what horizontal distance from the vessel does the stream from the upper hole collide with the stream from the lower hole?

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity  = 9.8 m/s²

the speed at each point

for upper hole    

                         v  = 19.29 m/s

lower hole      

                          v = 47.88 m/s

The path for each is parabolic

x = v t

we get

upper hole

 lower hole

 y for upper hole = 80 + y for lower hole

x = 109.32 meters

110 meters is the distance where they will intersect