The period of rotation of mercury in hours is 1407.6 hr. given that mereury has a radius of 2.4 x 10^6 m at its equator, what is the linear velocity (in m/s) at venus's surface? (enter the magnitude of the linear velocity at the equator.)

v=2.9578 m/s

Explanation:

t= 1407.6 hr

t = 3600 * 1407.6 = 5067360 s

w = 2π/T

    =2π/5067360

w = 1.24 x 10^-6 rad/s

v = r*w

v = 2.9758 m/s

answer; /// the above statement is (true);

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!