As light shines from air to another medium, i = 26.0 º. the light bends toward the normal and refracts at 32.0 º. what is the index of refraction?

a)0.827
b)0.944
c)1.21
d)1.06

The equation for the index of refraction is n = sin(theta1)/sin(theta2) where theta1 is the refracted angle and theta2 is the angle in a medium. Plugging in the values for the index of refraction, n = sin(32)/sin(26) we get 1.21. the answer is letter C. The index of refraction is always greater than 1.

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