Ineed with this.
a quarterback takes the ball from the line of scrimmage, runs backward for 10.0 yards, and then runs sideways parallel to the line of scrimmage for 15.0 yards. at this point, he throws a 50.0-yard forward pass straight down the field. what is the magnitude of the football’s resultant displacement?

with steps.

The magnitude of the football's resultant displacement is 42.72 yards.

The given parameters;

The resultant horizontal displacement, x = 50 yards - 10 yards = 40 yards

The resultant vertical displacement, y = 15 yards

The magnitude of the football's resultant displacement is calculated by applying Pythagoras theorem as shown below;

R² = y² + x²

R² = 40² + 15²

R² = 1,825

R = √1,825

R = 42.72 yards

Thus, the magnitude of the football's resultant displacement is 42.72 yards.

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I attached a pic that shows how :)

i would think klcio3

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.