Askier is pulled by a tow rope up a frictionless ski slope that makes an angle of 7.1° with the horizontal. the rope moves parallel to the slope with a constant speed of 0.60 m/s. the force of the rope does 600 j of work on the skier as the skier moves a distance of 4.6 m up the incline. (a) if the rope moved with a constant speed of 2.8 m/s, how much work would the force of the rope do on the skier as the skier moved a distance of 4.6 m up the incline? at what rate is the force of the rope doing work on the skier when the rope moves with a speed of (b) 0.60 m/s and (c) 2.8 m/s?

W = 600 J

Explanation:

Let's use the work equation to find the force

     W = f d

     F = W / d

     F = 600 / 4.6

     F = 130.4 N

a) The expression for power is

      P = W / t = f .v

      W = f v t

We need to calculate the rise time, which can be found by kinematics

      v = x / t

      t = x / v

      t = 4.6 /2.8

      t = 1.64 s

We calculate

     W = 130.4 2.8 1.64

     W = 600 J

b)  we repeat the calculations changing the speed  to v = 0.60m/s

      t = 4.6/0.6    

      t = 7.67 s

     W = 130.4 0.6 7.67

     W = 600 J

You can see that work is always the same what changes is the power

there are no correct statementd on the list of choices you provided.

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid