Abullet is fired vertically upward from a gun with an initial velocity of 225 m/s. how high does the bullet go in meters? [ignore air resistance]

h= 2582.9 m

Explanation:

bullet kinematics:  bullet moves with uniformly accelerated movement in freefall  

The negative sign in the equation indicates that the acceleration (g) is in the direction opposite to the movement of the  bullet.

v f₁²=v₀²-2g*h₁  Equation (1))

h: hight in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

Known data

v₀=  225 m/s

g= 9.8 m/s² : acceleration due to gravity

Problem development

When the  bulletl reaches the maximum height the final speed is equal to zero. vf=0

We replace data in the equation (1)

v f₁²=v₀²-2g*h₁

0 =  (225)²-2*9.8*h

2*9.8*h=(225)²

h= (225)²/ (2*9.8)

h= 2582.9 m

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