Hree boxes rest side-by-side on a smooth, horizontal floor. their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass in the center. a force of 50 n pushes on the 5.0-kg box, which pushes against the other two boxes. what magnitude force does the 5.0-kg box exert on the 3.0-kg box?

25 N

Explanation:

We are given that three boxes rest side-by-side on a smooth, horizontal floor.

Force applied on 5 kg box=50 N

We have to find the magnitude force exert on the 3 kg box by 5 kg box.

According to given question

When 5 kg box exert force on 3 kg box then equal and opposite force exert on 5 kg box due to 3 kg box and 2 kg box.

Let F be the force exert by 5 kg box on 3 kg box and

Hence, the magnitude force exert on 3 kg box by 5 kg box=25 N

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

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not copied too! hope this !

joke:

h o h o hope you have a merry christmas!