Amotorist drives north for 36.0 minutes at 96.0 km/h and then stops for 15.0 minutes. he then continues north, traveling 130 km in 2.20 h. (a) what is his total displacement? km
(b) what is his average velocity? km/h

a)

b)

Explanation:

First we convert our minutes to hours so we work always in the same units.

Where we used the fact that 1 hour are 60 min, thus the multiplying factor is equal to 1 (not altering the time, just changing the units).

a) On the first part the motorist travels a distance , and on the second part he travels .

The total displacement is

b) The average velocity is the relation between the total displacement and the time taken to cover it. Our total time is t=0.6h+0.25h+2.2h=3.05h, thus we have:

does anyone know or what?

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y