Ahawk flying at 11 m/s at an altitude of 132 m accidentally drops its prey. the parabolic trajectory of the falling prey is described by the equation y = 132 − x2 33 until it hits the ground, where y is its height above the ground and x is its horizontal distance traveled in meters. calculate the distance traveled by the prey from the time it is dropped until the time it hits the ground. express your answer correct to the nearest tenth of a meter.

s = 153.34 m

Explanation:

given,

speed of hawk flying = 11 m/s

altitude = 132 m

equation of parabolic trajectory

............at y = 0    x =66

integrating

using formula

s = 153.34 m

if the forces acting on an object are unbalanced, the object will accelerate in the direction of the net force on the object.

explanation:

this is best explained by having an understanding of newton's second law, which states that f=ma. you see, when the forces are unbalanced, net force (sum of all forces) is not zero. therefore making it necessary for the object to have an acceleration in the direction of the net force.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s