Acommuter airplane starts from an airport and takes theroute. the plane first flies to city a, located 175 km away in a direction 30.0° north of east. next, it flies for 150 km 20.0° west of north, to city b. finally, the plane flies 190 km due west, to city c. find the location of city c relative to the location of the starting point.

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc    where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

And the angle measure from the y-axis is:

So the answer is 245.45km in a direction 21.45° west of north from city A

490 n

f=125n a=2.5m/s2