Aworker kicks a flat rock lying on a roof. the rock slides up the incline 10.0 m to the apex of the roof, and flies off the roof as a projectile. what maximum height (in m) does the rock attain? assume air resistance is negligible, vi = 15.0 m/s, μk = 0.425, and that the roof makes an angle of θ = 42.0° with the horizontal. (assume the worker is standing at y = 0 when the rock is kicked.)

h = 7.42 m

Explanation:

deceleration of the rock

a = 9.65 m/s²

using formula

v² = u² + 2 a s

v² = 15² - 2×9.65 × 10

v = 5.66 m/s

the height attained is

h₁ =  10 sin θ

   = 10 sin 42

   = 6.69 m

now with vertical velocity it will reach to the height h₂

v y = v sin θ

     = 5.66 sin 42

     = 3.79 m/s

height is

v² = u² + 2 a s

0 = 3.79² - 2 × 9.8 ×h₂

h₂ = 0.73 m

the maximum height is

h = h₁ + h₂

  = 6.69 + 0.73

h = 7.42 m

newton's first law of motion

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.