Physics, 08.10.2019 18:00 mahogany139
He arrhenius equation shows the relationship between the rate constant k and the temperature t in kelvins and is typically written as k=ae−ea/rt where r is the gas constant (8.314 j/mol⋅k), a is a constant called the frequency factor, and ea is the activation energy for the reaction. however, a more practical form of this equation is lnk2k1=ear(1t1−1t2) which is mathematically equivalent to lnk1k2=ear(1t2−1t1) where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (t1 and t2). part a the activation energy of a certain reaction is 39.4 kj/mol . at 28 ∘c , the rate constant is 0.0140s−1 . at what temperature in degrees celsius would this reaction go twice as fast
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He arrhenius equation shows the relationship between the rate constant k and the temperature t in ke...
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