A2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. for both, the coefficient of static friction is 0.65. both cubes, initially neutral, are charged at a rate of 7.0 nc/s .

(a) which cube moves first?

(b) how long after charging begins does one cube begin to slide away?

(a).  The 2.0 g metal cube move fast than the 4 g metal cube.

(b). The time taken is 10.19 sec.

Explanation:

Given that,

Mass of metal cube = 2.0 g

Mass of second metal cube = 4.0 g

Coefficient of static friction = 0.65

Charging rate = 7.0 nC/s

Distance = 6.0 cm

(a). We need to calculate the frictional force for 2.0 g metal cube

Using formula of frictional force

Put the value into the formula

The frictional force for 4.0 g metal cube

The motion of the cube is less when the friction is more.

The 2.0 g metal cube is having less frictional force.

Therefore, the 2.0 g metal cube move fast than the 4 g metal cube.

(b). We need to calculate the time

Firstly we need to calculate the charge

Using electrostatic force and frictional force

Put the value into the formula

The time taken after charging beings is

Put the value into the formula

Hence, (a).  The 2.0 g metal cube move fast than the 4 g metal cube.

(b). The time taken is 10.19 sec.

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: