Two ships, a and b, leave port at the same time. ship a travels northwest at 21 knots and ship b travels at 25 knots in a direction 32° west of south. (1 knot = 1 nautical mile per hour; see appendix d.) what are (a) the magnitude (in knots) and (b) direction (measured relative to east) of the velocity of ship a relative to b? (c) after how many hours will the ships be 180 nautical miles apart? (d) what will be the bearing of b (the direction of the position of b) relative to a at that time? (for your angles, takes east to be the positive x-direction, and north of east to be a positive angle. the angles are measured from -180 degrees to 180 degrees. round your angles to the nearest degree.)

a) 38.8224 knots

b) 86° due north of east

c) 4.63 h

d) 86° due south of east

Explanation:

The velocity of B relative to A:

For the angle: It's on the first quadrant, so:

For the amount of time, we will use the relative velocity calculated:

The bearing of B relative to A will have the opposite direction of A relative to B, so:

α = -86°  This is 86° due south of east

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explanation:

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