Dr. john paul stapp was a u. s. air force officer who studied the effects of extreme deceleration on the human body. on december 10, 1954, stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s! calculate his acceleration and deceleration. express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity.

(a) Acceleration = 5.755 g

(b) Deceleration = 20.55 g

Explanation:

We have given that rocket accelerates from rest to 282 m/sec

So initial velocity u = 0 m/sec

And final velocity v = 282 m/sec

And time t = 5 sec

From first equation of motion v = u+at

So acceleration

We know that g = 9.8

So 56.4   =

(b) Now initial velocity u = 282 m/sec

And finally it comes to rest so final velocity v = 0 m/sec

Time t = 1.4 sec

So acceleration a

So deceleration = 201.428

We know that g = 9.8

So 201.428   =

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.