Acart rolling down an incline that is 60 meters long. if the cart has a beginning speed of 2.0 m/s and it
speeds up to 22 m/s. what was the cart's acceleration?

4 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 2.0 m/s

v = 22 m/s

Find: a

v² = v₀² + 2aΔx

(22 m/s)² = (2.0 m/s)² + 2a (60 m)

a = 4 m/s²

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j