Asimple elevator ride can teach you quite a bit about the normal force as this rider below can (hopefully) tell you. there are three different scenarios given, detailing the rider\'s experience in an unnamed hotel. for each scenario, calculate the normal force, fn,1-3, acting on the rider if his mass is m = 76.6 kg and the acceleration due to gravity g = 9.81 m/s2. in scenario 1, the elevator has constant velocity. in scenario 2 the elevator is moving with upward acceleration a2 = 4.84 m/s2. finally, in scenario 3, unfortunately for the rider, the cable breaks and the elevator accelerates downward at a3 = 9.81 m/s2.

fn1=
fn2=
fn3=

FN1=751.45 N

FN2=370.74 N

FN3=751.45 N

Explanation:

The formula to apply in this case is;

Normal Force=product of mass of the body and acceleration due to gravity

F=ma where m is the mass of the body and a is acceleration due to gravity

In 1.

Mass = 76.6 kg  and g=9.81 m/s²

Force, F1= 76.6*9.81=751.45 N

In 2

Mass =76.6 kg   and a=4.84 m/s²

Force , F2 = 76.6*4.84=370.74 N

In 3

Mass = 76.6 kg and a=9.81

Force F3=76.6*9.81=751.45 N

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.