Abowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. after the collision, the bowling ball leaves with a momentum of +13 kg • m/s

+17 kg m/s

Explanation:

Question is missing. Found it on google:

"What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg?"

Solution:

we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:

where

is the momentum of the ball before the collision

is the momentum of the pin before the collision (zero because the pin is stationary)

is the momentum of the ball after the collision

is the momentum of the pin after the collision

Solving the equation for , we find:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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