The terminals of a 0.70 vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm what is the current in the wire?

I = 11.26 mA

Explanation:

given,

V = 0.7 V           length = 80 m

diameter   = 0.2 mm = 0.02 cm

radius = 0.01 × 10⁻² m

ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C

A = cross sectional area = π r² = π (0.01 × 10⁻² )²

    = 31.4× 10⁻⁹ m²

R = 62.165 Ω

I = 11.26 mA

scientific laws are the result of testing theories and proving them to be facts.

a=d/t

a="triangle"v/t

explanation:

a = acceleration