An electric flux of 147 n*m^2/c passes through a flat horizontal surface that has an area of 0.824 m^2. the flux is due to a uniform electric field. what is the magnitude of the electric field if the field points 31.6° above the horizontal?

231.16 N/C

Explanation:

Given

Electric Flux

Area(A)

Given Field point above

Therefore angle between Area vector Electric Field =90-31.6=

We know that Flux is given by

E=231.16 N/C

the answer is false

explanation:

c)as speed changes, wavelength and frequency change.

everything changes!