Kalea throws a baseball directly upward at time t = 0 at an initial speed of 13.7 m/s. how high h does the ball rise above its release point? ignore air resistance and use g = 9.80 m/s^2.

h = 9.57 seconds

Explanation:

It is given that,

Initial speed of Kalea, u = 13.7 m/s

At maximum height, v = 0

Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :

t = 1.39 s

Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

Here, a = -g

h = 9.57 meters

So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.

the answer is a. at the equator

neither accurate nor precise.