Periodic comets are lose aggregates of rock and ice on elliptical orbits around the sun as they approach perihelion, comets heat-up and lose gas and dust particles that, pushed by radiation pressure, form the comet's tails. if a periodic comet on a keplerian orbit with eccentricity e loses a dust particle at perihelion, the particle will be pushed on a new orbit with the same perihelion distance but a larger eccentricity: where β-frad/f,1 is the radiation pressure coefficient for the dust grain. i. find the expression for the semi-major axis a, of a dust particle lost at perihelion, as a function of β and of the original semi-major axis a and eccentricity e of the comet 2. find an expression for the minimum value of b so that the dust particle is ejected by the system (i. e. set on a parabolic orbit)

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j