Afootball is kicked from ground level with an initial velocity of 22.2 m/s at angle of 31.0° above the horizontal. how long, in seconds, is the football in the air before it hits the ground?

t = 1.66 seconds

Explanation:

Initial velocity of the football, u = 22.2 m/s

Angle above the horizontal,

Let is the vertical component of the velocity,

Let t is the time for which the football in the air before it hits the ground. It can be calculated as :

v = 0

t = 1.66 seconds

Hence, this is the required solution.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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