Physics, 05.10.2019 00:00 khalilh1206
An fcc metal has a lattice spacing of a-3.060 angstroms. calculate the volume (in angstroms) of the interstices (empty space) in the unit cell. volume of the interstices-volume of the unit cell (1-atomic packing factor) where the atomic packing factor for fcc metals is 0.74 änd the volume of a unit cell with the side a will be a 8.9966
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An fcc metal has a lattice spacing of a-3.060 angstroms. calculate the volume (in angstroms) of the...
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