Acharge q is transferred from an initially uncharged plastic ball to an identical ball 12 cm away. the force of this attraction is then 17 mn. how many electrons were transferred from one ball to another?

the answer would be c

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j