Abrave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 n on him. the mass of the losing player plus equipment is 86 kg, and he is accelerating at 2.6 m/s2 backward. randomized variables f = 780 n m1 = 86 kg m2 = 118 kg a = 2.6 m/s2 show answer no attempt 50% part (a) what is the magnitude of the force of friction, in newtons, between the losing player's feet and the grass as he slides backwards?

Explanation:

Mass of the losing player with its all equipment is given as

M = 86 kg

Net force applied on him by another player is given as

F = 780 N

also we know that acceleration of the losing player is given as

now by Newton's 2nd law we will have

answer; i believe that the correct answer is (d) a very small amount of mass

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.