Consider two wheels with fixed hubs. the hub cannot move, but the wheel can rotate about it. the hubs are fixed to a stationary object. the hubs and spokes are massless, so that the moment of inertia of each wheel is given by i = mr2 , where r is the radius of the wheel. each wheel starts from rest and has a force applied tangentially at its rim. wheel a has a mass of 1.0 kg, a diameter of 1.0 m, and an applied force of 1.0 n. wheel b has a mass of 1.0 kg and a diameter of 2.0 m. the two wheels undergo identical angular accelerations. what is the magnitude of the force applied to wheel b?

Magnitude of force on wheel B is 4 N

Explanation:

Given that

For wheel A

m= 1 kg

d= 1 m,r= 0.5 m

F=1 N

We know that

T= F x r

T=1 x 0.5 N.m

T= 0.5 N.m

T= I α

Where I is the moment of inertia and α is the angular acceleration

T= I α

0.5= 0.25 α

For Wheel B

m= 1 kg

d= 2 m,r=1 m

Given that angular acceleration is same for both the wheel

T= I α

T= 1 x 2

T= 2 N.m

Lets force on wheel is F then

T = F x r

2 = F x 1

So F= 2 N

Magnitude of force on wheel B is 2 N

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