Kepler's third law relates the period of a planet
to its orbital radius r, the constant g in newton's law of gravi-
tation (f = gm1m2/r^2), and the mass of the sun m.. what com-
bination of these factors gives the correct dimensions for the
period of a planet?

√(r³ / (MG))

Explanation:

The dimensions of each variable are:

r = [m]

G = [m³/kg/s²]

M = [kg]

Multiplying M and G eliminates kilograms:

MG = [m³/s²]

The radius cubed divided by MG eliminates meters:

r³ / (MG) = [s²]

The square root gives us seconds:

√(r³ / (MG)) = [s]

momentum of soft ball three times less than baskey ball

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.