Achild bounces a 52 g superball on the sidewalk. the velocity change of the superball is from 20 m/s downward to 14 m/s upward. if the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? answer in units of n.

Force on superball will be

Explanation:

We have given mass of superball m = 52 gram = 0.052 kg

Velocity change from 20 m/sec downward to 14 m/sec upward

Let downward velocity is positive then upward velocity is negative

So downward velocity is + 20 m/sec and upward velocity is -14 m/sec

Time is given as 1800 sec

We know that acceleration is rate of change of velocity

So

According to newton second law

Force = ma = 0.052×0.0188

as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )

it becomes positively charged by charging it