The black mamba is one of the world’s most poisonous snakes, and with a maximum speed of 18.0 km/h, it is also the fastest. suppose a mamba waiting in a hide-out sees prey and begins slithering toward it with a velocity of +18.0 km/h. after 2.50 s, the mamba realizes that its prey can move faster than it can. the snake then turns around and slowly returns to its hide-out in 12.0 s. calculate the mamba's average velocity for the complete trip.

From hide-out toward prey:

Speed = 18 km/hr=5 m/s. ... Time = 2.5 sec. ... Distance= s*t = 12.5 meters

From turn-around back to hide-out:

Distance = 12.5 m. ... Time = 12.0 sec

Average speed = (total distance covered) / (time to cover the distanced)

total distance = (12.5 + 12.5) = 25 meters

total time = (2.5 + 12.0) = 14.5 sec

Average speed = (25 m) / (14.5 sec) = 1.72 m/s

Average velocity = displacement / time

The creature ended up where it started, so its displacement is zero.

Average velocity = ( 0 / 14.5 sec )

Average velocity = zero

t.                 w               e                 n                   t                 y                 c             h               a           r           a               c                 t             e             r             s        

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.