After a photon is generated in the core of the sun, it travels a short distance and interacts with another particle. the interaction causes a photon to travel in a different direction. over large distances and many interactions, the photon's path resembles that of a stumbling drunk person. if a photon generated in the center of the sun's core can only travel about 0.02 cm before the next interaction, what is the minimum amount of times the photon will interact before reaching the convection zone? assume the diameter of the core is 25 percent of the sun's diameter and use the radius of the sun (6.96 × 108 m).

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.