During a softball game, a player running from second base to third base reaches a speed
of 4.5 m/s before she starts to slide into third base. when she reaches third base 1.3s
after beginning her slide, her speed is reduced to 0.6 m/s.
a. what is the player's acceleration during the slide?

I would say it would be 3.9

but i believe there is something missing shorty.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s