A1.1-kg object is suspended from a vertical spring whose spring constant is 160 n/m. (a) find the amount by which the spring is stretched from its unstrained length. (b) the object is then pulled straight down by an additional distance of 0.26 m and released from rest. find the speed with which the object passes through its original position on the way up.

3.14 m/s

Explanation:

We are given that

Mass of object=1.1 Kg

Spring constant=160 N/m

a.We have to find the amount by which the spring is stretched from its unstrained length(it means x)

We know that F=kx ,

b.When an object is pulled straight down by an additional distance 0.26 m and released from rest.

x=0.26 m

We have to find the speed with which the object passes through its original position on the way up.

(Law of conservation of energy)

Substitute the values then we get

Hence, the speed of an object with which the object passes through its original position on the way up=3.14 m/s

i believe the answer would be:

d. violin, clarinet, french horn, and tuba

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min