If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (p=0vi=1^ 2 r= v^ 2 r )

1/4

Explanation:

P = IV, and V = IR, so P = I²R.

If R is held constant, and I is cut in half, then power becomes:

P = (I/2)²R

P = 1/4 I²R

So the power reduces by a factor of 4.

the answer is d

lies a supermassive black hole called sagittarius a*, or sgr a* for short.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s