Aflashlight is held at the edge of a swimming pool at a height of 1.5 m such that its beam makes an angle of 39 degrees with respect to the water's surface. the pool is 2.75 m deep and the index of refraction for air and water are 1 and 1.33, respectively. what is the horizontal distance from the edge of the pool to the bottom of the pool where the light strikes? write your answer in meters.

The horizontal distance from the to the bottom of the pool is 3.831 m

Solution:

As per the question;

Height of the pool, H = 1.5 m

Depth of the pool, D =   2.75 m

Refractive index  of air,

Refractive index  of air,

Angle of the beam at the water surface,

Now,

The angle of incidence is given by

Now, using Snell's law:

Now,

From the normal, the horizontal image distance, d' is given by:

Now,

From the normal, the horizontal object distance, d'' is given by:

Thus the horizontal distance is given by:

d' + d'' = 1.979 + 1.852 =3.831 m

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.