Afish swimming in a horizontal plane has velocity v with arrowi = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r with arrowi = (16.0 î − 3.00 ĵ) m. after the fish swims with constant acceleration for 15.0 s, its velocity is v with arrow = (25.0 î − 3.00 ĵ) m/s. (a) what are the components of the acceleration of the fish? ax = m/s2 ay = m/s2 (b) what is the direction of its acceleration with respect to unit vector î? ° counterclockwise from the +x-axis (c) if the fish maintains constant acceleration, where is it at t = 30.0 s? x = m y = m in what direction is it moving? ° counterclockwise from the +x-axis

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Iagree c would be the answer

Ibelieve the answer is b