Abaseball slugger hits a pitch and watches the ball fly into the bleachers for a home run, landing h = 9.5 m higher than it was struck. when visiting with the fan that caught the ball, he learned the ball was moving with final velocity vf = 30.15 m/s at an angle θf = 29° below horizontal when caught. assume the ball encountered no air resistance, and use a cartesian coordinate system with the origin located at the ball's initial position.

The ball's position can get of the initial angle when leave the bat and velocity magnitud.

θ = 35,1

v = 36,5

Explanation:

θf= 29

h= 9,5 m

vf= 30,15

Now as you know the vector in 'y' can be related with Tan function

So, the initial velocity in 'y' can be resolved:

Finally the velocity is going to be:

θ

θ

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .