Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 å. the atom is placed in a (a) simple cubic, (b) fcc, (c) bcc, and (d) diamond lattice. as- suming that nearest atoms are touching each other, what is the lattice constant of each lattice?

What do you mean there’s no jelly beans

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Your answer would be false