Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare time–when they\'re not sleeping or eating–joyfully scampering about on the cage\'s floor. bryce tracks his mice\'s health diligently and just now recorded their masses as 0.0225 kg, 0.0223 kg, 0.0197 kg, and 0.0127 kg. at this very instant the x and y components of the mice\'s velocities are, respectively, (0.869 m/s, -0.283 m/s), (-0.883 m/s, -0.253 m/s), (0.345 m/s, 0.803 m/s), and (-0.555 m/s, 0.205 m/s). calculate the x and y components of bryce\'s mice\'s total momentum, px and py.

For problems 1-3, consider a simple dc brush motor with a permanent magnet stator. with an an consider a simple dc brush motor with a permanent magnet ae supply voltage of 100 v, the no-load speed of the motor is 1000 rpm. this motor can provide a torque of 1.9 n-m at 800 rpm drawing a current of 2 a current are both zero at no load.) 1. with an armature supply voltage of 100 v, the motor is operated at 900 rpm. what is the motor torque? what is the mechanical power delivered by the motor? what is the current draw? what is the electrical power input? what is the energy efficiency of the motor? with an armature supply voltage of 100 v, the motor is operated at 1100 rpm (where it acts as a generator). what torque input is required? what mechanical power is required what current is generated? what is the electrical power generated? what is the energy efficiency of the motor acting as a generator? 2. with an armature supply voltage raised to 120 v, the motor is operated at 1000 rpm. what is the no-load speed? what is the motor torque? what is the mechanical power delivered by the motor? what is the current draw? what is the electrical power input what is the energy efficiency of the motor? 3.

True or false when elements combine to form a mixture, the resulting chemical properties may be very different from those of the elements that make it.

What is the electric force acting between two charges of -0.0045 c and -0.0025 c that are 0.0060 m apart? use fe=kq1q2/r^2 and k = 9.00 x 10^9 n*m^2/c^2 a. 1.7 x 10^7 n b. -1.7 x 10^7 n c. -2.8 x 10^9 n d. 2.8 x 10^9 n