The captain of a plane wishes to proceed due west. the cruising speed of the plane is 256 m/s relative to the air. a weather report indicates that a 44.3-m/s wind is blowing from the south to the north. in what direction, measured with respect to due west, should the pilot head the plane?

Angle = 9.965° South of West.

In the question,

The speed of the Plane w.r.t to Wind = 256 m/s

Speed of the Wind w.r.t to Ground = 44.3 m/s

Direction of Wind = North from South

Direction Plane wishes to go = West

So,

Using the vectors,

Speed of Wind w.r.t Ground is given by,

Resultant speed of Plane w.r.t Ground is given by,

So,

From the Vector's Triangle Sum property,

Therefore, the plane has to move in the direction of 'III quadrant' or 'South-West' direction.

Now,

In the triangle, using Pythagoras Theorem,

The speed of the plane = 252.13 m/s

Now,

Therefore, the angle at which the plane should fly to go West is = 9.965° South of West.

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..