Along cylindrical shell (radius = 2.0 cm) has a charge uniformly distributed on its surface. if the magnitude of the electric field at a point 8.0 cm radially outward from the axis of the shell is 85 n/c, how much charge is distributed on a 2.0-m length of the charged cylindrical surface?

Explanation:

Applying Gauss' Law to a cylindrical shell of radius 8 cm and height h, concentric to the charged shell, we get:

Where is the charge per unit length, and so is the charge inside the shell, and if we set we can get the answer to our question.

Solving for we get:

plugging in the values ( in SI units) we get:

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.