Amotor cycle starting from rest has an acceleration of 2.6 m s 2 when the motorcycle has traveled a distance of 120 m it slows down with an acceleration of 1.5 m s 2 until its velocity is 12 m s what is the total displacement of the motorcycle

280.33 m

Explanation:

Given

motorcycle starts from rest

initial acceleration

distance traveled =120 m

velocity gain during this time, let say v

after it starts decelerating with 1.5 m/s^2 [/tex]

final velocity()=12 m/s

12=25+(-1.5)t

t=8.667 s

distance traveled during this time

Therefore total displacement=

i believe the answer is a hope it and is correct