Along cylindrical rod of diameter 200 mm with thermal conductivity of 0.5 w/m·k experiences uniform volumetric heat generation of 2.4 x 104 w/m3 . the rod is encapsulated by a circular sleeve having an outer diameter of 400 mm and a thermal conductivity of 4 w/m·k. the outer surface of the sleeve is exposed to cross flow of air at 27°c with a convection coefficient of 25 w/m2·k. (a) find the temperature at the interface between the rod and sleeve and on the outer surface. (b) what is the temperature at the center of the rod?

The speed was not exceeded so it was slow

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!