We want to hydrolyze 500 lb per day of an ester at an initial concentration of 5 m (the ester has a molecular weight of 130) in aqueous basic solution in a batch process, and we need product that is 99% hydrolyzed. in benchtop experiments in a flask, we find that 50% of the ester hydrolyzes in 15 min for initial ester concentrations of either 1 or 5 m. we also find that, when we react for 8 h, all of the ester has hydrolyzed. it takes 1 h to empty the reactor and refill and heat it to start another batch. what size reactor will we need?

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.

Hi. i believe this is called a scientific  theory.cheers!